Implement Alarm on subscription fail

Raise an alarm if subscription request fails.

Change-Id: Ibfb97bca48d75deccb889317cc26a984779eab37
Signed-off-by: subhash kumar singh <subh.singh@samsung.com>

diff --git a/hwApp.go b/hwApp.go
index b368db9..260b7c1 100755 (executable)
--- a/hwApp.go
+++ b/hwApp.go
@@ -23,6 +23,7 @@ package main
 import (
        "encoding/json"
 
+       "gerrit.o-ran-sc.org/r/ric-plt/alarm-go.git/alarm"
        "gerrit.o-ran-sc.org/r/ric-plt/xapp-frame/pkg/clientmodel"
        "gerrit.o-ran-sc.org/r/ric-plt/xapp-frame/pkg/xapp"
 )
@@ -160,6 +161,13 @@ func (e *HWApp) sendSubscription(meid string) {
 
        if err != nil {
                xapp.Logger.Error("subscription failed (%s) with error: %s", meid, err)
+
+               // subscription failed, raise alarm
+               err := xapp.Alarm.Raise(8086, alarm.SeverityCritical, meid, "subscriptionFailed")
+               if err != nil {
+                       xapp.Logger.Error("Raising alarm failed with error %v", err)
+               }
+
                return
        }
        xapp.Logger.Info("Successfully subcription done (%s), subscription id : %s", meid, *resp.SubscriptionID)