* 10 subframes, which would have otherwise caused
* the check to succeed for a possibly older process.
*/
- if ((proc->tbInfo[0].timingInfo.subframe == sf->sfNum) ||
- (proc->tbInfo[1].timingInfo.subframe == sf->sfNum))
+ if ((proc->tbInfo[0].timingInfo.slot == sf->sfNum) ||
+ (proc->tbInfo[1].timingInfo.slot == sf->sfNum))
{
/*
* Later, if a proc can be scheduled without having an